In a resonance tube experiment, two successive resonances are heard at 15 cm 48 cm. End correction will be
In a resonance tube experiment, two successive resonances are heard at 15 cm 48 cm. End correction will be
A. 1.5cm
B. 3cm
C. 2.5cm
D. 1cm
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Correct Answer - A
`rho=(l_2-3l_1)/(2) = (48-3xx15)/)(2)`
`rho = (48-45)/(2) = 3/2 = 1/5cm`
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