If ΔABC ~ ΔDEF, ∠A + ∠B = 130°, then ∠F = …………  (A) 130°  (B) 140° (C) 50°  (D) 40°

Correct option is (C) 50°

Given that \(\triangle ABC\sim\triangle DEF\)

\(\therefore\) \(\angle D=\angle A,\)

\(\angle E=\angle B\)

& \(\angle F=\angle C\)

Now in \(\triangle ABC,\)

\(\angle A+\angle B+\angle C\) \(=180^\circ\)  (Sum of angles in a triangle)

\(\Rightarrow\) \(\angle A+\angle B+\angle F\) \(=180^\circ\)         \((\because\angle C=\angle F)\)

\(\Rightarrow\) \(130^\circ+\angle F=180^\circ\)      \((\because\angle A+\angle B=130^\circ)\)

\(\Rightarrow\) \(\angle F=180^\circ-130^\circ\)

\(=50^\circ\)

Correct option is: (C) 50°