If ΔABC ~ ΔDEF, BC = 4 cm, EF = 5 cm area of ΔABC = 80 cm^2, then area of ΔDFF = ………… cm^2
If ΔABC ~ ΔDEF, BC = 4 cm, EF = 5 cm area of ΔABC = 80 cm2, then area of ΔDFF = ………… cm2
(A) 64
(B) 125
(C) 144
(D) 169
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Correct option is (B) 125
Given that \(\triangle ABC\sim\triangle DEF,\) BC = 4 cm, EF = 5 cm and \(ar(\triangle ABC)=80\,cm^2\)
\(\therefore\) \(\frac{ar(\triangle DEF)}{ar(\triangle ABC)}=(\frac{EF}{BC})^2\)
\(\Rightarrow\) \(\frac{ar(\triangle DEF)}{80}=(\frac54)^2\) (Given)
\(\Rightarrow\) \(ar(\triangle DEF)=\frac{25}{16}\times80\)
\(=25\times5=125\,cm^2\)
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