When two tuning fork are sounded together produce x beats/s. The fequency of A is `n_(A)`. The fork B is loaded with little wax then x-1 number of bea

Question

When two tuning fork are sounded together produce x beats/s. The fequency of A is `n_(A)`. The fork B is loaded with little wax then x-1 number of bea

When two tuning fork are sounded together produce x beats/s. The fequency of A is `n_(A)`. The fork B is loaded with little wax then x-1 number of beats per second are produced, then the frequency of fork B before loading will be
A. `2n_(A)x`
B. `n_(A) + x`
C. `n_(A) + 2x`
D. `n_(A) - x`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - B
`n_(B) = n_(A) +-x`
`n_(B) = n_(A) + x or n_(A) - x`
when `n_(B)` is loaded with little wax and sounded with `n_(A)`
`n_(B) = n_(A) +-x`
`n_(B) = n_(A) + x or n_(A) -x`
After loading frequency decreases, before loading frequency increases. Therefore frequency of tuning fork before loading is,
`n_(B) = n_(A) + x`