A reaction has an activation energy of 209 KJ `"mol"^(-1)` . The rate increase 10-fold when the temperature is increased from `27^(@)C` to `X ""^(@)C` . The temperature X is closed to
[Gas constant, R =`8.314 J "mol"^(-1) K^(-1)`]
A. 35
B. 40
C. 30
D. 45

4 views

1 Answers

Correct Answer - A
`log_(10)=(209xx10^(3))/(2.303xx8.314)[(1)/(300)-(1)/(T)]`
`9.16xx10^(-5)=3.33xx10^(-3)-(1)/(T)`
`T=308.4 K`
or `35^(@)C=X`

4 views

Related Questions