The capillary rises are found to be in the ration of 3:2 when two capillary tubes are immersed in water of surface tension `7.2xx 10^(-2)` N/m . The ratio of the bore diameters of the capillary tubes is
A. `2:3`
B. `3:2`
C. `4:9`
D. `9:4`

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Correct Answer - A
`(r_(1))/(r_(2)) = (h_(2))/(h_(1)) = 2/3 `

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