The work done is breaking a water drop of radius 1 cm into 64 equal droplets
(Surface tension of water is 0.07 N/m)
A. `1.6 xx 10^(-4)`J
B. `264 xx 10^(-4)`J
C. `2.64 xx 10^(-4)`J
D. `5.28 xx 10^(-4)`J

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Correct Answer - C
`dw= 4piR^(2)(n^(1//3)-1)T`
` = 4piR^(2)(64^(1//3)-1)T`
` = 12 piR^(2)T`
` =12 xx pixx (1xx 10^(-2))^(2) xx0.07`
` = 12xx 22/7 xx 7xx10^(-2) xx10^(-4)`
` = 2.64 xx10^(-4)`J

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