A film is held on a ring of area 0.05 `m^(2)` of liquid of surface tension 0.05 N/m then the surface energy is

Question

A film is held on a ring of area 0.05 `m^(2)` of liquid of surface tension 0.05 N/m then the surface energy is

A film is held on a ring of area 0.05 `m^(2)` of liquid of surface tension 0.05 N/m then the surface energy is
A. 25 J
B. `0.01` J
C. `0.5` J
D. `25xx10^(-4)`J

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Surface energy , `= 4piR^(2)T`
` = 0.05 xx 0.05 ` N/m
` = 25 xx10^(-4)` J

4 views Answered 2023-02-05 15:29