The number of moles of `Br_(2)` produced when two moles of potassium permanganate are treated with excess potassium bromide in aqueous acid medium is-

Question

The number of moles of `Br_(2)` produced when two moles of potassium permanganate are treated with excess potassium bromide in aqueous acid medium is-

The number of moles of `Br_(2)` produced when two moles of potassium permanganate are treated with excess potassium bromide in aqueous acid medium is-
A. 1
B. 3
C. 2
D. 4

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`KMnO_(4)+KBr+H_(2)SO_(4)toMnSO_(4)+K_(2)SO_(4)+Br_(2)+H_(2)O`
Balanced equations
`2KMnO_(4)+10KBr+8H_(2)SO_(4)to2MnSO_(4)+5Br_(2)+6K_(2)SO_(4)+8H_(2)O`
`Eq. of KMnO_(4)=Eq.ofBr_(2)`
`"Mole"xxn="Mole"xxn`
`2xx5="Mole"xx2
5 moles of `Br_(2)` are formed

5 views Answered 2023-02-05 15:29