A particle is executing SHM with and frequency of `(1)/(8)` Hz. If it starts from the mean position at time t = 0, the ratio of distances convered by

Question

A particle is executing SHM with and frequency of `(1)/(8)` Hz. If it starts from the mean position at time t = 0, the ratio of distances convered by

A particle is executing SHM with and frequency of `(1)/(8)` Hz. If it starts from the mean position at time t = 0, the ratio of distances convered by it in 1st and 2nd seconds is
A. 1
B. `1//(sqrt(2)-1)`
C. `1//(sqrt(3)-1)`
D. `sqrt(2)-1`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`n=(1)/(8)HzimpliesT=8s`
Mean to extreme t = 2s. The distance covered by it in 1 second is `y_(1)` and in the II second `=A-y_(1)`.
`(y_(1))/(A-y_(1))=(Asin.(2pi)/(8)xx1)/(A-Asin.(2pi)/(8)xx1)=(A//sqrt(2))/(A-A//sqrt(2))=(1)/(sqrt(2)-1)`

4 views Answered 2023-02-05 15:29