A solid sphere rolls without slipping down a `30^(@)` inclined plane. If `g=10 ms^(-2)` then the acceleration of the rolling sphere is

Question

A solid sphere rolls without slipping down a `30^(@)` inclined plane. If `g=10 ms^(-2)` then the acceleration of the rolling sphere is

A solid sphere rolls without slipping down a `30^(@)` inclined plane. If `g=10 ms^(-2)` then the acceleration of the rolling sphere is
A. `5ms^(-2)`
B. `(7)/(25)ms^(-2)`
C. `(25)/(7)ms^(-2)`
D. `(15)/(7)ms^(-2)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`a=(g sin theta)/(1+(K^(2))/(R^(2)))=(10 sin 30^(@))/(1+(2)/(5))=(25)/(7)ms^(-2)`.

4 views Answered 2023-02-05 15:29