The escape velocity from the earth is about 11 km/s. The escape velocity from a planet having twice the radius and the twice mean density as the earth

Question

The escape velocity from the earth is about 11 km/s. The escape velocity from a planet having twice the radius and the twice mean density as the earth

The escape velocity from the earth is about 11 km/s. The escape velocity from a planet having twice the radius and the twice mean density as the earth, is
A. 31 km/s
B. 11 km/s
C. 22 km/s
D. 15.5 km/s

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

The escape velocity on the surface of the earth is 11.2 `kms^(-1)`. If mass and radius of a planet is 4 and 2 tims respectively than that of the earth

2 Answers 4 Views

The escape velocity form the earth is 11 `kms^(-1)` the esacpe velocity from a planet having twice the radius and the same mean denisty as the earth w

2 Answers 4 Views

If the density of the planet is double that of the earth and the radius 1.5 times that of the earth, the acceleration due to gravity on the planet is

2 Answers 4 Views

The escape velocity of a body from the earth is `V_(e)`. The escape velocity of a planet whose mass and radius are twice those of the earth is

2 Answers 4 Views

The escape velocity for the earth is 11.2 km / sec . The mass of another planet is 100 times that of the earth and its radius is 4 times that of the e

2 Answers 4 Views

A planet has twice the radius but the mean density is `1/4` th as compared to earth. What is the ratio of escape velocity from earth to that from the

2 Answers 4 Views

String B has twice the length , twice the diameter twice the tension and twice the density of string A. Then the overtone of B that will be in unison

2 Answers 4 Views

The density of a newly discovered planet is twice that of the earth. The acceleration due to gravity at the surface of the planet is equal to that at

2 Answers 4 Views

The escape velocity from a spherical satellite is `v_(e)`. The escape velocity from another satellite of double the radius and half the mean density w

2 Answers 4 Views

The escape velocity of a body on the surface of the earth is `V_(e)`. What is the escape velocity on a planet whose radius is thrice the radius of the

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - a
`(v_(e_(2)))/(v_(e_(1)))=(R_(2))/(R_(1))sqrt((rho_(2))/(rho_(1)))=2sqrt2`
`=2xx11xxsqrt2=22xx1.414=31.108`

5 views Answered 2023-02-05 15:29