Two brass balls of masses 2 kg and 0.5 kg experience a force of attraction of 2 N. When the distance between their centres is doubled. Then the force of attraction is
A. 1/2 N
B. 1/4 N
C. 1 N
D. 2 N

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1 Answers

Correct Answer - a
`(F_(2))/(F_(1))=((r_(1))/(r_(2)))^(2)=((r_(1))/(2r_(1)))^(2)=(1)/(4)`
`F_(2)=(2)/(4)=0.5N`

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