A `100 kg` car is moving with a maximum velocity of `9 m//s` across a circular track of radius 30 m . The maximum force of friction between the road a
A `100 kg` car is moving with a maximum velocity of `9 m//s` across a circular track of radius 30 m . The maximum force of friction between the road and the car is
A. 1000 N
B. 706 N
C. 270 N
D. 200 N
4 views
1 Answers
Correct Answer - C
Maximum force of friction = centripetal force
`(mv^(2))/(r)=(100xx(9)^(2))/(30)=270 N`.
4 views
Answered