On passing `SO_2` in solution of `K_2Cr_2O_7` , it turn green due to the formation of
A. `K_2Cr_2O_4`
B. Chromic acid
C. `Cr_2(SO_4)_3`
D. `FeSO_4`

4 views

1 Answers

Correct Answer - C
`K_2Cr_2O_7 + H_2SO_4 + 3SO_2 to K_2SO_4 + Cr_2(SO_4)_3 + H_2O`

4 views