Find out two-third `(2//3)` life of a first order reaction in which `k=5.48 xx 10^(-14)s^(-1)`
A. `2.01xx10^(11)s`
B. `2.01xx10^(13)s`
C. `8.08xx10^(13)s`
D. `16.04xx10^(11)s`

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1 Answers

Correct Answer - B
For two- third of a reaction,
`[A]_(o)=a,[A]=a-(2a)/(3)rArra=(a)/(3)`
`t_(2//3)=(2.303)/(k)"log"[A]_o/[A]=(2.303)/(k)"log"(a)/(a)=(2.303)/(k)log3`
`t_(2//3)=(2.303xx0.4771)/(5.48xx10^(-14))=2.01xx10^(13)s`

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