The rate constant for the reaction
`2N_(2)O_(5)to4NO_(2)+O_(2), "is"" " 3.0xx10^(-5)S^(-1)`. If the rate is
`2.40xx10^(-5)"mol"L^(-1)s^(-1)` then the concentration of
`N_(2)O_(5)("in mol" L^(-1))` is
A. 1.4
B. 1.2
C. 0.04
D. 0.8

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1 Answers

Correct Answer - D
For a first order reaction
`Rate =k[N_(2)O_(5)]`
`2.4xx10^(-5)=3.0xx10^(-5)[N_(2)O_(5)]`
`[N_(2)O_(5)]=(2.4xx10^(-5))/(3.0xx10^(-5))=0.8 "mol" L^(-1)`

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