The equilibrium constannt of a reaction is 0.008 at 298 K. the standard energy change of the reaction at the same temperature is
A. `-11.96kJ`
B. `-5.43kJ`
C. `-8.46kJ`
D. `+11.96kJ`

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1 Answers

Correct Answer - D
Standard free energy change,
`DeltaG^(@)=-2.303RTlogK_(c)`
`=-2.303xx8.314xx298xxlog` 0.008
`=+11965.16J=11.96kJ`

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