The G.M. of two positive numbers is 6. Their arithmetic mean A and harmonic mean H satisfy the equation `90A+5H=918`, then A may be equal to (A) `5/2`

Question

The G.M. of two positive numbers is 6. Their arithmetic mean A and harmonic mean H satisfy the equation `90A+5H=918`, then A may be equal to (A) `5/2`

The G.M. of two positive numbers is 6. Their arithmetic mean A and harmonic mean H satisfy the equation `90A+5H=918`, then A may be equal to (A) `5/2` (B) 10 (C) 5 (D) `1/5`
A. `(1)/(5)`
B. 5
C. `(5)/(2)`
D. 10

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A::D
`:.G=6` and `G^(2)=AH`
`implies H=(36)/(A)`
Given, `90A+5H=918`
`implies 90A+5xx(36)/(A)=918" " implies 5A+(10)/(A)=51`
`implies 5A^(2)-51A+10=0" " implies (A-10)(5A-1)=0`
`:.A=10,(1)/(5)`

4 views Answered 2023-02-05 15:29