Arrange the following molecules in the increasing order of bond angle. `underset(I)(H_(2)O) underset(II)(H_(2)S)underset(III)(H_(2)Se) underset(IV)(H_

Question

Arrange the following molecules in the increasing order of bond angle. `underset(I)(H_(2)O) underset(II)(H_(2)S)underset(III)(H_(2)Se) underset(IV)(H_

Arrange the following molecules in the increasing order of bond angle.
`underset(I)(H_(2)O) underset(II)(H_(2)S)underset(III)(H_(2)Se) underset(IV)(H_(2)Te)`
A. `I lt II lt III lt IV`
B. `IV lt III lt II lt I`
C. `I lt III lt II lt IV`
D. `IV lt II lt III lt I`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
lp-bp repulsion is maximu, in `H_(1)Te` due to least electronegativity of Te and minimum in `H_(2)O` due to high electronegavity of O.

5 views Answered 2023-02-05 15:29