The bond order of `H_(2)^(-)` ion is `(1)/(2)`. If it has 2 bonding electrons, how many antibonding electrons it will have ?
The bond order of `H_(2)^(-)` ion is `(1)/(2)`. If it has 2 bonding electrons, how many antibonding electrons it will have ?
A. 3
B. 1
C. 2
D. 4
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Correct Answer - B
As bond order `=(1)/(2)(N_(b)-N_(a))`
`:. N_(a)=N_(b)-2xx ` bond order
`=2-2xx(1)/(2) or N_(a)=1`
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