A carbon film resistor has colour green, black, violet and gold . The value of the resistor is
A. `50 M Omega`
B. `500 M Omega`
C. `(500 pm 5%) M Omega`
D. `(500pm 10%)M Omega`

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Correct Answer - C
Corresponding to the colours of the first and second bands green and black, the figure are 5 and 0. Corresponding to the colour of third band, violet, the multiplier is `10^(7)`. Therefore, the value of the resistance is `50xx10^(7)Omega`. The gold colour of the fourth band indicates the tolerance of 5%. So, that the value of the resistor is written as,
`50xx10^(7) Omega pm 5% = 500 xx 10^(6)Omega+5%=500 pm 5% M Omega`

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