Light of wavelength `6328 Å` is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :

Question

Light of wavelength `6328 Å` is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :

Light of wavelength `6328 Å` is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :
A. `0.36^(@)`
B. `0.18^(@)`
C. `0.72^(@)`
D. `0.09^(@)`

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
The angular half-width of central maxima is given by
`sin theta=(lambda)/(a)`
`rArr theta=(6328xx10^(-10))/(0.2xx10^(-3))` rad
`rArr theta=(6328xx10^(-10)xx180)/(0.2xx10^(-3)xx pi)"degree"=0.180^(@)`

4 views Answered 2023-02-05 15:29