A mass of dry air at NTP is compressed to (1)/(20)th of its original volume suddenly . If `gamma=1.4` , the final pressure would be

Question

A mass of dry air at NTP is compressed to (1)/(20)th of its original volume suddenly . If `gamma=1.4` , the final pressure would be

A mass of dry air at NTP is compressed to (1)/(20)th of its original volume suddenly . If `gamma=1.4` , the final pressure would be
A. 20 atm
B. 66.28 atm
C. 30 atm
D. 150 atm

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
From `p_(2)V_(2)^(gamma)=p_(1)V_(1)^(gamma)`
`rArr" " p_(2)=P_(1)((V_(1))/(V_(2)^(gamma)))^(gamma)=1((V_(1))/(1//20V_(1)))^(1.4)`
=66.28 atm

5 views Answered 2023-02-05 15:29