The temperature at which the velocity of oxygen will be half of hydrogen at NTP is
A. `1092^(@)C`
B. `1492^(@)C`
C. `273^(@)C`
D. `819^(@)C`

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1 Answers

Given , `v_(O_(2))=(1)/(2)V_(H_(2))`
`therefore" " sqrt((3RT)/(32))=(1)/(2)sqrt((3Rxx273)/(2))`
`(T)/(32)=(273)/(8)`
` therefore" " T=4xx273`
`T=1092K=1092-273`
`T=819^(@)C`

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