A tangential force of 0.25 N is applied to a 5 cm cube to displace its upper surface with respect to the bottom surface. The shearing stress is

Question

A tangential force of 0.25 N is applied to a 5 cm cube to displace its upper surface with respect to the bottom surface. The shearing stress is

A tangential force of 0.25 N is applied to a 5 cm cube to displace its upper surface with respect to the bottom surface. The shearing stress is
A. `10 Nm^(-2)`
B. `50 Nm^(-2)`
C. `75 Nm^(-2)`
D. `100 Nm^(-2)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - d
Shearing stress
`= (F)/(A) = (25 xx 10^(-2))/(25 xx 10^(-4)) = 100 Nm^(-2)`

5 views Answered 2023-02-05 15:29