A point object is placed at a distance of 10 cm and its real image is formed at a distance of 20 cm from a concave mirror. If the object is moved by 0
A point object is placed at a distance of 10 cm and its real image is formed at a distance of 20 cm from a concave mirror. If the object is moved by 0.1 cm towards the mirror, the image will shift by about
A. 0.4 cm away from the mirror
B. 0.8 cm away from the mirror
C. 0.4 cm towards the mirror
D. 0.8 cm towards the mirror
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Correct Answer - A
From the relation,
`(1)/(v)+(1)/(u)=(1)/(f)`
We have, `(-dv)/(v^(2))-(du)/(u^(2))=0`
`therefore " " dv=(v^(2))/(u^(2))(-du)=((20)/(10))^(2) (0.1)=0.4 cm " "` (away from the mirror)
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