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`CuSO_(4).5H_(2)O` is blue in colour while `CuSO_(4)` is colourless. Why ?
A. presence of strong field ligand in `CuSO_(4) * 5H_(2)O`
B. absence of water (ligand) , `d-d` transitions are not possible in `CuSO_(4)`
C. anhydrous `CuSO_(4)` undergoes d-d transitions due to crystal field splitting
D. colour is lost due to loss of unpaired electrons .

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Correct Answer - A
In `CuSO_(4) * 5H_(2)O` water acts as ligand and as a result it causes crystal field splitting making d-d transitions possible in `CuSO_(4) * 5H_(2)O` . Hence , it is coloured . In anhydrous `CuSO_(4)` , due to absence of ligand crystal field splitting is not possible hence no colour is observed .

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