In a reaction `2HI to H_(2) + I_(2)` the concentration of HI decreases from 0.5 mol `L^(-1)` to 0.4 mol `L^(-1)` in 10 minutes. What is the rate of re
In a reaction `2HI to H_(2) + I_(2)` the concentration of HI decreases from 0.5 mol `L^(-1)` to 0.4 mol `L^(-1)` in 10 minutes. What is the rate of reaction during this interval?
A. `5 xx 10^(-3) M "min"^(-1)`
B. `2.5 xx 1-^(-3) M "min"^(-1)`
C. `5 xx 10^(-1) M "min"^(-1)`
D. `2.5 xx 10^(-2) M "min"^(-1)`
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Correct Answer - A
Average rate `= - (1)/(2) (Delta[R])/(Delta t) = - (1)/(2) xx (0.4 - 0.5)/(10)`
`= (1)/(2) xx (0.1)/(10) = 5 xx 10^(-3) M "min"^(-1)`
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