A 0.001 molal solution of `[Pt(NH_(3))_(4)CI_(4)]` in water had a freezing point depression of `0.0054^(@)C`. If `K_(f)` for water is `1.80`, the corr

Question

A 0.001 molal solution of `[Pt(NH_(3))_(4)CI_(4)]` in water had a freezing point depression of `0.0054^(@)C`. If `K_(f)` for water is `1.80`, the corr

A 0.001 molal solution of `[Pt(NH_(3))_(4)CI_(4)]` in water had a freezing point depression of `0.0054^(@)C`. If `K_(f)` for water is `1.80`, the correct formulation for the above molecule is
A. `[Pt(NH_3)_4Cl_3]Cl`
B. `[Pt(NH_3)_4Cl_4]`
C. `[Pt(NH_3)_4Cl_2]Cl_2`
D. `[Pt(NH_3)_4Cl]Cl_3`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`DeltaT_f=ixxK_fxxm`
0.0054=`ixx1.8xx0.001 rArr `i=3
Since it gives 3 particles on dissociation the correct formula of the molecule is `[Pt(NH_3)_4Cl_2]Cl_2`

4 views Answered 2023-02-05 15:29