The energy of activation for a first order reaction is 104 kJ `mol^(-1) ` The rate constant at `25^(@) C` is `3.7 xx 10^(-5) s^(-1)` . What is the rat

Question

The energy of activation for a first order reaction is 104 kJ `mol^(-1) ` The rate constant at `25^(@) C` is `3.7 xx 10^(-5) s^(-1)` . What is the rat

The energy of activation for a first order reaction is 104 kJ `mol^(-1) ` The rate constant at `25^(@) C` is `3.7 xx 10^(-5) s^(-1)` . What is the rate constant at `30^(@) C`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

Activation energy for the acid catalysed hydrolysis of sucrose is `6.22 kJ mol^(-1)`, while the activation energy is only `2.15 kJ mol^(-1)` when hydr

2 Answers 4 Views

Activation energy of the reaction `AtoB+38KCal` is 20KCal. Then activation energy of reaction `BtoA` bill be :-

2 Answers 5 Views

Half life of a first order reaction and a zero order reaction are same. Then the ratio of the initial rate of the first order reaction to that of zero

2 Answers 5 Views

A first order gas -phase reaction has an energy of activation of 240 kJ `mol^(-1)` . If frequency factor of the reaction is `1.6 xx 10^(13) s^(-1)` ,

2 Answers 9 Views

The rate constant of a first order reaction at `25^(@) C` is `0.24 s^(-1)` if the energy of activation of the reaction is 88 ` kJ mol^(-1)` at what te

2 Answers 5 Views

A first order reaction has activation energy 22.8 kJ at 300 K . If the rate constant of the reation is `1.42 xx 10^(2) min^(-1)` Calculate the frequen

2 Answers 5 Views

In a first order reaction, the concentration of reactant decrease from 400 mol `L^(-1)` to 25 mol `L^(-1)` in 200 seconds. The rate constant for the r

2 Answers 4 Views

The activation energy for a reaction at temperature T K was found to be or `2.303 "RT J mol"^(-1)`. The ratio of the rate constant to Arrhenius factor

2 Answers 4 Views

The rate constant of a reaction increases by 5% when its temperature is raised from `27^@c` to `28^@c.` The activation energy of the reaction is

2 Answers 4 Views

The activation energy of a reaction is zero. Its rate constant at 280 K is `16 xx 10^(-6) s^(-1)` the rate constant at 300k is

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - Rate constant at `30^(@) C = 7.4 xx 10^(-4) s^(-1)`
Given : Energy of activation `=E_(a) =104 kJ mol^(-1) = 104 xx 10^(3) j mol^(-1)`
Initial rate constant = `k_(1) = 3.7 xx 10^(-5) s^(-1)`
Initial temperature = `T_(1)= 273 + 25 = 298 K`
Final temperature =`T_(2) = 273 + 30 = 303 K`
Final rate constant = `k_(2) = ?`
`log_(10) .(k_(2))/(k_(1)) = (E_(a) (T_(2)- T_(1)))/(2.303 R xx T_(1) xx T_(2))`
`= (104xx 10^(3) xx (303 - 298))/(2.303 xx 8.314 xx 298 xx 303) = (104 xx 10^(5) xx 5)/(2.303 xx 8.314 xx298 xx 303) =0.3`
`:. (k_(2))/(k_(1)) = AL 0.3 = 1.995 ~= 2`
`:. k_(2) = 2 xx k_(1) = 2xx 3.7 xx 10^(-5) = 7.4 xx 10^(-4) s^(-1)`