The decay constant , for a given radioactive sample, is 0.3465 `"day"^(-1)` .What percentage of this sample will get decayed in a period of 4 days ?

Question

The decay constant , for a given radioactive sample, is 0.3465 `"day"^(-1)` .What percentage of this sample will get decayed in a period of 4 days ?

The decay constant , for a given radioactive sample, is 0.3465 `"day"^(-1)` .What percentage of this sample will get decayed in a period of 4 days ?
A. `100%`
B. `50%`
C. `75%`
D. `10%`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - c
Here, `lambda=0.3465 "day"^(-1) ` ,t=4 days
`T_(1//2)=0.693/lambda=0.693/0.3465`=2 days
`therefore n=1/T_(1//2)=4/2`=2
Hence, sample left decayed after a period of 4 days.
`N/N_0=(1/2)^2 =(1/4)`=25%
`therefore ` Sample decayed = 75%

4 views Answered 2023-02-05 15:29