The mass of `._3^7Li` is 0.042 amu less than the sum of masses of its constituents. The binding energy per nucleon is
A. 5.586 MeV
B. 10.522 MeV
C. 2.433 MeV
D. 3.739 MeV

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1 Answers

Correct Answer - a
Binding energy, `E_b` of `._3^7Li=Deltam` x 931 MeV
= 0.042 x 931 MeV
Binding energy per nucleon=`(0.042xx931)/7`
=5.586 MeV

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