Two nuclei have their mass numbers in the ratio of 1:3. The ratio of their nuclear densities would be
Two nuclei have their mass numbers in the ratio of 1:3. The ratio of their nuclear densities would be
A. `(3)^(1//3):1`
B. `1:1`
C. `1:3`
D. `3:1`
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Correct Answer - b
`A_1:A_2 = 1:3`
Their radii will be in the ratio
`R_0A_1^(1//3) : R_0A_2^(1//3)=1:3^(1//3)`
Density,`rho=A/(4/3piR^3)`
`therefore rho_(A_1):rho_(A_2)=1/(4/3 piR_0^3. 1^3):3/(4/3piR_0^3(3^(1//3))^3)=1:1`
Their nuclear densities will be the same .
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