A parallel plate capacitor has a uniform electric field E in the space between the the plates. If the distance between the plates is d and area of each plate is A, the energy stored in the capacitor is
A. `(1)/(2)epsi_(0)E^(2)`
B. `(E^(2)Ad)/(epsi_(0))`
C. `1/2epsi_(0)E^(2)Ad`
D. `eisi_(0)E^(2)Ad`

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1 Answers

Correct Answer - C
Capacitacne of a parallel plate capacitor is `C = (epsi_(0)A)/(d) " "………(i)`
Potential difference between the plates is V = Ed
The energy stored in the capacitor is
`U = (1)/(2) CV^(2) = (1)/(2) ((epsi_(0)A)/(d)) (Ed)^(2) " "("using (i) and (ii)")`
` = (1)/(2) epsi_(0) E^(2) Ad`

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