Two particles are oscillating along two close parallel straight lines side by side, with the same frequency and amplitudes. They pass each other, moving in opposite directions when their displacement is half of the amplitude. The phase difference is:-
A. `pi/6`
B. 0
C. `(2pi)/(3)`
D. `pi`

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1 Answers

Correct Answer - C
`X=A sin omegat`
`A/2 =A sin omega t implies sin omegat =1/2 `
so phase `omegat =30^(@) 120^(@)or (2pi)/(3)`

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