A lens has a power of 10 D, when placed in air. When it is immersed in water `(mu =(4)/(3))` the change in power is (refractive index of lens material

Question

A lens has a power of 10 D, when placed in air. When it is immersed in water `(mu =(4)/(3))` the change in power is (refractive index of lens material

A lens has a power of 10 D, when placed in air. When it is immersed in water `(mu =(4)/(3))` the change in power is (refractive index of lens material is 1.5)
A. 2.55 D
B. 5.0 D
C. `+7.5 D `
D. `6.67 D `

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`P _(air) =(1)/(f_(air))`
`P _(water) =(mu_("water"))/(f_("water"))impliesP_("water")= (4//3)/(4f _("ari"))=(P _(air))/(3)impliesP_("water")`
`=3.33D`
Change is power `=100-3.33D = 6.67D`

7 views Answered 2023-02-05 15:29