The resultant ampiltude of a vibrating particle by the superposition of the two waves `y_(1) = a sin ( omega t + (pi)/(3)) and y_(2) = a sin omega t`

Question

The resultant ampiltude of a vibrating particle by the superposition of the two waves `y_(1) = a sin ( omega t + (pi)/(3)) and y_(2) = a sin omega t`

The resultant ampiltude of a vibrating particle by the superposition of the two waves `y_(1) = a sin ( omega t + (pi)/(3)) and y_(2) = a sin omega t` is :
A. a
B. `sqrt(2)_(a)`
C. `2a`
D. `sqrt(3)_(a)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Resultant amplitude `= 2a cos ((pi//3)/(2)) = sqrt(3a)`

4 views Answered 2023-02-05 15:29