An radioactive atom `(""_(Z)X^(A))` undergoes `alpha `-decay then ratio of energy of α-particle and daughter nuclei increases with increase in :-

Question

An radioactive atom `(""_(Z)X^(A))` undergoes `alpha `-decay then ratio of energy of α-particle and daughter nuclei increases with increase in :-

An radioactive atom `(""_(Z)X^(A))` undergoes `alpha `-decay then ratio of energy of α-particle and daughter nuclei increases with increase in :-
A. `A^(2)`
B. `A^(0) `
C. `A`
D. `A^(-1) `

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
In `alpha ` decay , `(E _(K ) )alpha=((A-4 )/(A))Q`
`(E _(K ))_("daughter ")=((4)/(A))Q`
` therefore ((E_(K))alpha)/((E_(K))_("daughter "))=(A-4)/(4)`

4 views Answered 2023-02-05 15:29

An radioactive atom `(""_(​Z)​X^(​A)​)` undergoes `alpha `-decay then ratio of energy of α-particle and daughter nuclei increases with increase in :-

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An radioactive atom `(""_(Z)X^(A))` undergoes `alpha `-decay then ratio of energy of α-particle and daughter nuclei increases with increase in :-