In a two-digit number, digit in units place is twice the digit in tens place, if 27 is added to it, digits are reversed. Find the number.
In a two-digit number, digit in units place is twice the digit in tens place, if 27 is added to it, digits are reversed. Find the number.
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Let ten's digit = x
Unit's digit = 2x
Required Number = 10x + 2x = 12x
On Interchanging the Digit's Number = 10 (2x) + x = 21x
According to The Question
⇒ 12x + 27 = 21x
⇒ 27 = 21x - 12x
⇒ 27 = 9x
⇒ 27/9 = x
⇒ 3 = x
Required Number = 12 × 3 = 36
Hence, the number required number is 36.
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