What is value of Boyle's temperature of ethane gas when \( a =5.489 dm ^{6} atm mol ^{-2} \) and \( b =0.0638 dm ^{3} \) atm mol" (a) \( 1048 K \) (b) \( 104.8 K \) (c) \( 209.6 K \) (d) \( 290.6 K \)

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1 Answers

Given,

a = 5.489 dm6 atm mol-2

b = 0.0638 dm3

R = 0.082 L atm K-1 mol-1

Boyle's temp Tb = a/Rb

T\(=\frac{5.489}{0.082\times0.0638}\)

Tb = 1049.52 K

Option (b) is correct.

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