A first order reaction is 50% completed in 20 minutes at `27^(@)`C. The energy of activation of the reaction is-

Question

A first order reaction is 50% completed in 20 minutes at `27^(@)`C. The energy of activation of the reaction is-

A first order reaction is 50% completed in 20 minutes at `27^(@)`C. The energy of activation of the reaction is-
A. 43.58 KJ
B. 55.14 KJ
C. 11.97 KJ
D. 6.65 KJ

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`"Log"((K_(2))/(K_(1)))=(Ea)/(2.303R)((1)/(T_(1))-(1)/(T_(2)))`
`Log4=(Ea)/(2.303xx8)((1)/(300)-(1)/(320))`
`{K_(1)=(1n2)/(20),K_(2)=(n2)/(5)}`

4 views Answered 2023-02-05 15:29