The activation energy for the reaction - `H_(2)O_(2)toH_(2)O+(1)/(2)O_(2)` is `18 K cal//mol` at 300 K. calculate the fraction of molecules of reacton
The activation energy for the reaction -
`H_(2)O_(2)toH_(2)O+(1)/(2)O_(2)`
is `18 K cal//mol` at 300 K. calculate the fraction of molecules of reactonts having energy equal to or greater than activation energy ?
Anti log `(-13.02)=9.36xx10^(-14)`
A. `9.36xx10^(-14)`
B. `1.2xx10^(-12)`
C. `4.2xx10^(-16)`
D. `5.2xx10^(-15)`
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