The weight of 350 ml a diatomic gas at `0^(@)C` and 2atm pressure is 1 gm.The weight of one atom is :-
The weight of 350 ml a diatomic gas at `0^(@)C` and 2atm pressure is 1 gm.The weight of one atom is :-
A. `(16)/(N_(A))`
B. `(32)/(N_(A))`
C. `16N_(A)`
D. `32N_(A)`
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Correct Answer - A
PV = nRT
` (2xx350)/(1000) = (1)/(Mw)xx0.082xx273`
Mw = 32
wt of molecule of diatomic molecule `A_(2) = (32)/(N_(A))`
wt of 1 atom of diatomic molecule
` A_(2) = (32)/(N_(A))xx(1)/(2)=(16)/(N_(A))`
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