A potential difference of `10^(3)` V is applied across an X-ray tube. The ratio of the de-Broglie wavelength of the incident electrons to the shortest

Question

A potential difference of `10^(3)` V is applied across an X-ray tube. The ratio of the de-Broglie wavelength of the incident electrons to the shortest

A potential difference of `10^(3)` V is applied across an X-ray tube. The ratio of the de-Broglie wavelength of the incident electrons to the shortest wavelength of X-rays products is -
`(e//m=1.8xx10^(14)C//kg`for an electron)
A. `1//20`
B. `1//100`
C. 1
D. None of these

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
For incident electron
`lambda_(1) =(h)/(p) =(h)/sqrt(2Km)=(h)/(sqrt(2m Ve))`
and shortest wavelength of X- rays is `lambda_(2)=(hc)/(Ve)`
`(lambda_(1))/(lambda_(2))=1/c sqrt(((V)/(2))((e)/(m)))`
Substituting the value we get `(lambda_(1))/(lambda_(2)) =1`

4 views Answered 2023-02-05 15:29