Let \( f: R \rightarrow R \) be defined by \( f(x)=\frac{x-1}{2} \) and, \( g: R \rightarrow R \) be defined by \( g(x)=2 x+1 \). Then, \( \frac{d}{d x}[(g \circ f)(7)]= \) (a) 1 (b) 0 (c) \( -1 \) (d) None of these

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Let \( f: R \rightarrow R \) be defined by \( f(x)=\frac{x-1}{2} \) and, \( g: R \rightarrow R \) be defined by \( g(x)=2 x+1 \). Then, \( \frac{d}{d x}[(g \circ f)(7)]= \) (a) 1 (b) 0 (c) \( -1 \) (d) None of these

Monjur Alahi

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2025-01-04 04:42

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

f(7) = 7-1/2 = 6/2 = 3

(gof)(7) = g(f(7))

= g(3)

= 2 x 3 + 1

= 7

Hence, option (d) is correct.

4 views Answered 2023-02-05 15:29