Heat of combustion of two isomer x and y are 17 kJ/mol and 12 kJ/mol respectively. From this information it may be concluded that :
A. isomer x is 5 kJ/mol more stable
B. isomer y is 5kJ/mol less stable
C. isomer y has 5 kJ/mol more potential energy
D. isomer x is 5n kJ/mol less stable

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Correct Answer - D
Stability `prop(1)/("heat of combution")`

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