The circular measure of an angle of an isoscles triangle is `(5pi)/(9)`, Circular measure of one of the angle angles must be(समद्विबाहु त्रिभुज के एक
The circular measure of an angle of an isoscles triangle is `(5pi)/(9)`, Circular measure of one of the angle angles must be(समद्विबाहु त्रिभुज के एक आसमान कोण की माप `(5pi)/(9)` रेडियम है तो शेष दो सामान कोनो में से प्रत्येक कोण की माप बताये )
A. `(5pi)/(18)`
B. `(5pi)/(9)`
C. `(2pi)/(9)`
D. `(4pi)/(9)`
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Correct Answer - c
`(5pi)/(9)=(5xx180^(@))/(9)rArr100^(@)`
Other two angle must be `40^(@)+40^(@)40^(@)=40^(@)=(2pi)/(9)`
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