Let X is a continuous random variable with probability density function `f(x)={{:(x/6+k,0lexle3),(0," otherwise"):}` The value of k is equal to

Question

Let X is a continuous random variable with probability density function `f(x)={{:(x/6+k,0lexle3),(0," otherwise"):}` The value of k is equal to

Let X is a continuous random variable with probability density function
`f(x)={{:(x/6+k,0lexle3),(0," otherwise"):}`
The value of k is equal to
A. `1/(12)`
B. `1/3`
C. `1/4`
D. `1/6`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`oversetoounderset(-oo)intf(x)dx=1rArr0+overset3underset0int(x/6+k)dx+0=1`
`rArr" "[x^2/(12)+kx]_0^3=1rArr3/4+3k=1`
`rArr" "3k=1/4rArrk=1/(12)`

4 views Answered 2023-02-05 15:29