Calculate the energy of the reaction ,
`Li^(7) + p to 2 _(2)He^(4)`
If the binding energy per nucleon in `Li^(7)` and `He^(4)` nuclei are 5.60 MeV and 7.06 MeV , respectively .
A. 19.6 MeV
B. 2.4 MeV
C. 8.4 MeV
D. 17.28 MeV

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1 Answers

Correct Answer - D
Binding energy of Li = 39.20 MeV
Binding energy of `He^(4)` = 28.24 MeV
Binding energy of `` = 56.48 MeV
`therefore` Energy = 56.48 - 39.20 = 17.28 MeV

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